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Hydraulics Calculators

Hydraulic Calculators

Free Hydraulic Calculators & Engineering Tools

Calculate hydraulic cylinder force, speed, flow, pump requirements, hydraulic horsepower, motor performance and related hydraulic-system values — in Imperial or metric, with every step of the math shown.

Hydraulic Cylinder Calculator

in
in
in
PSI
GPM

Theoretical push force 25,133 lbf, pull force 18,850 lbf.

Theoretical Push Force

25,133lbf

≈ 12.57 US tons

Theoretical Pull Force

18,850lbf

≈ 9.42 US tons

Actual available force and speed may differ due to pressure losses, back pressure, seal friction, leakage, component efficiency, temperature, wear and other system conditions.

Force

Push Force
25,133 lbf
Pull Force
18,850 lbf
Push Tonnage
12.57 US tons
Pull Tonnage
9.42 US tons

Speed & Time

Extend Speed
3.06 in/s
Retract Speed
4.08 in/s
Extend Time
7.83 s
Retract Time
5.88 s
Full Cycle Time
13.71 s

Cylinder Geometry

Piston Area
12.57 in²
Rod Area
3.142 in²
Annular Area
9.425 in²

Oil Volume

Extend Chamber Volume
1.306 gal (301.6 in³)
Retract Chamber Volume
0.979 gal (226.2 in³)
Total Displaced Volume Per Full Cycle
2.285 gal (527.8 in³)

Theoretical Hydraulic Power

Hydraulic Power at Entered Pressure & Flow11.67 HP

This is fluid power only. The motor or engine driving the pump will need more, because pumps, motors and the rest of the system are not 100% efficient.

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Hydraulic Calculations Made Simple

Two numbers do most of the work in a hydraulic system. Pressure primarily determines available force — the harder the oil pushes on an area, the more force you get. Flow primarily determines actuator speed — the more oil you send per minute, the faster a cylinder fills and moves.

Real systems don't behave perfectly. Pressure drops through hoses and valves, back pressure on the return side, seal friction, internal leakage and relief valve settings all change what actually reaches the load. The calculator above gives theoretical values — a solid starting point, not a guarantee.

How hydraulic cylinder force is calculated

Force = pressure × area. When a cylinder extends, oil pushes on the whole piston face, so the area is π × bore² ÷ 4. With pressure in PSI and area in square inches, the answer is in pounds-force (lbf). In metric, bar × 0.1 gives N/mm², and N/mm² × mm² gives newtons.

Why retract force is lower on a single-rod cylinder

On the rod side, the rod itself covers the middle of the piston. Oil can only push on the ring around it — the annular area, equal to piston area minus rod area. Same pressure, smaller area, less force. A bigger rod means a bigger difference between push and pull.

How hydraulic flow affects cylinder speed

Speed = flow ÷ effective area. One US gallon is 231 cubic inches, so GPM × 231 ÷ 60 gives cubic inches per second. Divide that by the area being filled and you get inches per second. Double the flow and, in theory, you double the speed.

Why retract speed is usually higher than extend speed

With the same flow going to either end, the rod side has less volume to fill for every inch of travel because the rod occupies some of it. Less volume per inch means the piston moves faster on the way back.

How cylinder chamber volume is calculated

Volume = effective area × stroke. The cap end holds piston area × stroke; the rod end holds annular area × stroke. Divide cubic inches by 231 for US gallons. This oil moves in and out as the cylinder cycles — it returns to the reservoir rather than being consumed — but the reservoir and pump must be able to supply the difference between the two chambers.

What theoretical hydraulic horsepower means

Hydraulic horsepower (PSI × GPM ÷ 1,714) is the power carried by the moving, pressurised oil. It is not the size of the engine or electric motor you need. Pumps are not 100% efficient, and heat and other losses mean the prime mover must supply more than this figure.

Why actual machine performance may differ

Pressure losses in lines, fittings and valves, back pressure, seal friction, leakage past the piston, pump wear, oil temperature and viscosity, and relief settings can all reduce real-world force and speed. Always check against manufacturer data for the components you are using.

Frequently Asked Questions

How do you calculate hydraulic cylinder force?

Multiply the pressure by the area it acts on. For extending, that is the full piston area (π × bore² ÷ 4). In Imperial units, PSI × square inches gives pounds-force. A 4 in bore at 2,000 PSI gives about 25,133 lbf of theoretical push force.

Why does a hydraulic cylinder have less force when retracting?

On a single-rod cylinder, the rod takes up part of the piston on the rod side, so pressure only acts on the ring-shaped annular area (piston area minus rod area). Less area at the same pressure means less force.

How does GPM affect hydraulic cylinder speed?

Speed equals flow divided by the area being filled. Doubling the flow doubles the theoretical speed. In Imperial units, convert GPM to cubic inches per second (GPM × 231 ÷ 60), then divide by the effective area in square inches.

How do you calculate hydraulic cylinder cycle time?

Divide the stroke by the extend speed to get extend time, and by the retract speed to get retract time. Add the two for a theoretical full cycle. This assumes the full supplied flow reaches the cylinder the whole time.

How much oil does a hydraulic cylinder hold?

The cap-end chamber holds piston area × stroke; the rod-end chamber holds annular area × stroke. Divide cubic inches by 231 for US gallons. The oil circulates back to the reservoir — it isn't used up.

How do you calculate hydraulic horsepower?

Hydraulic horsepower = PSI × GPM ÷ 1,714 (in metric, kW = bar × L/min ÷ 600). This is theoretical fluid power. The engine or electric motor driving the pump needs more to cover pump and system losses.